How Much House Can You Afford? Mortgage Payment Problem

Finance & Interest 11th-12th Grade
Problem
You can afford a 1,450 per month mortgage payment. You've found a 30-year loan at 8% interest. What's the maximum price of a house that you can afford (assuming no down payment)? Round your answer to the nearest cent.

What You Will Learn

  • How to apply the present value of annuity formula to mortgage calculations
  • Converting between annual and monthly interest rates in financial problems
  • Understanding the relationship between payment capacity and borrowing power
  • Working with compound interest in reverse—from payments to principal
  • Interpreting mortgage mathematics that underlies every home purchase

Visualizing the Problem

You can afford a 1,450 per month mortgage payment. You've found a 30-year loan at 8% interest. What's the maximum...

The loan amount today equals the present value of all future payments discounted at the interest rate.

Solution: Method 1 — Present Value of Annuity Formula

This is a classic mortgage calculation where we need to find the present value of a stream of future payments. The key insight is that a loan is simply the present value of all the payments the borrower will make.

Step 1 — Convert the annual interest rate to monthly

Since mortgage payments are made monthly, we need the monthly interest rate:

Monthly rate = Annual rate ÷ 12
r = 8% ÷ 12 = 0.08 ÷ 12 = 0.006667

Step 2 — Calculate the total number of payments

For a 30-year loan with monthly payments:

n = 30 years × 12 months/year = 360 payments

Step 3 — Apply the present value of annuity formula

The present value formula for an ordinary annuity is:

PV = PMT × [(1 - (1 + r)^(-n)) / r]

Where PV = present value (loan amount), PMT = monthly payment ($1,450), r = monthly rate (0.006667), n = number of payments (360)

Step 4 — Calculate the bracket term

Let's compute the complex part step by step:

(1 + r)^(-n) = (1.006667)^(-360) = 0.0907
1 - (1 + r)^(-n) = 1 - 0.0907 = 0.9093
[(1 - (1 + r)^(-n)) / r] = 0.9093 ÷ 0.006667 = 136.029

Step 5 — Calculate the maximum house price

Now we can find the present value:

PV = $1,450 × 136.029 = $197,242.05

Rounding to the nearest cent: $197,242.05

Solution: Method 2 — Geometric Series Approach

We can also think of this as a geometric series problem. Each payment has a different present value depending on when it's made.

Step 1 — Set up the series

The present value of all payments is:

PV = 1450/(1.006667)¹ + 1450/(1.006667)² + ... + 1450/(1.006667)³⁶⁰

Step 2 — Factor out the payment amount

This becomes:

PV = 1450 × [1/1.006667 + 1/(1.006667)² + ... + 1/(1.006667)³⁶⁰]

Step 3 — Recognize the geometric series

The bracket is a geometric series with first term a = 1/1.006667 and common ratio r = 1/1.006667:

Sum = a × (1 - r^n) / (1 - r)
= (1/1.006667) × (1 - (1/1.006667)³⁶⁰) / (1 - 1/1.006667)

Step 4 — Simplify the expression

After algebraic manipulation, this reduces to the same formula:

Sum = (1 - (1.006667)^(-360)) / 0.006667 = 136.029

Step 5 — Complete the calculation

Therefore:

PV = $1,450 × 136.029 = $197,242.05
Maximum house price: $197,242.05

Verification

Let's verify by checking that $197,242.05 borrowed at 8% annual interest results in exactly $1,450 monthly payments over 30 years.

Forward calculation check

Using the standard mortgage payment formula:

PMT = P × [r(1 + r)^n] / [(1 + r)^n - 1]
PMT = 197,242.05 × [0.006667 × (1.006667)³⁶⁰] / [(1.006667)³⁶⁰ - 1]
PMT = 197,242.05 × [0.006667 × 11.023] / [11.023 - 1]
PMT = 197,242.05 × 0.07349 / 10.023
PMT = 197,242.05 × 0.007333 = $1,450.00 ✓

Total payments check

The borrower will pay $1,450 × 360 = $522,000 total over 30 years. The interest paid is $522,000 - $197,242.05 = $324,757.95, which represents about 165% of the original loan amount—typical for a 30-year mortgage at 8%.

Does This Seem Reasonable?

Let's put this answer in perspective. At $1,450 per month, this borrower will pay $17,400 per year. A house price of about $197,000 means the annual payments are roughly 8.8% of the home's value.

Compare this to some boundary cases:

  • If interest were 0%: The maximum loan would simply be $1,450 × 360 = $522,000
  • If the loan term were infinite: The maximum would approach $1,450 ÷ 0.006667 = $217,500 (just enough for interest-only payments)
  • Our answer ($197,242): Falls reasonably between these extremes, closer to the interest-only limit because 8% is relatively high

The fact that the borrower ends up paying $522,000 total for a $197,242 house illustrates why mortgage interest is such a significant factor in home affordability.

Common Pitfalls

✗ Using annual rate instead of monthly rate
Some students use PV = $1,450 × [(1 - (1.08)^(-30)) / 0.08] = $16,311. This treats the $1,450 as an annual payment, not monthly. Always convert to monthly rates for monthly payments.
✗ Using 30 periods instead of 360
Using n = 30 instead of 360 gives PV = $1,450 × [(1 - (1.006667)^(-30)) / 0.006667] = $37,518. This calculates as if there were only 30 payments total instead of 30 years of monthly payments.
✗ Forgetting the "no down payment" assumption
The $197,242.05 is the maximum house price when no down payment is made. Some students calculate this as the loan amount, then ask "but what about the down payment?" The problem specifically states "no down payment," so loan amount equals house price.

The Broader Principle

This problem demonstrates the fundamental relationship in all loan calculations:

Present Value = Payment × Present Value Factor

Where PV Factor = [1 - (1 + r)^(-n)] / r

This formula works for any annuity: mortgages, car loans, lottery payouts, lease payments, or retirement planning. The present value factor depends only on the interest rate and number of payments—not on the specific dollar amounts.

For reference, here are common PV factors for 8% annual interest:

  • 15 years monthly: Factor = 104.64
  • 30 years monthly: Factor = 136.03 (our problem)
  • 30 years annually: Factor = 11.26

Notice how the 30-year monthly factor is much larger than the 30-year annual factor—that's the power of more frequent compounding working in the borrower's favor.

What If?

1
Shorter Term, Same Budget

What if you wanted a 15-year loan instead of 30 years, keeping the same $1,450 monthly payment? What's the maximum house price you could afford at the same 8% interest?

Step 1 — Same monthly rate and payment

We still have r = 0.006667 and PMT = $1,450, but now n = 15 × 12 = 180 payments

Step 2 — Calculate new PV factor

(1 - (1.006667)^(-180)) / 0.006667 = (1 - 0.3018) / 0.006667 = 104.64

Step 3 — Find maximum house price

PV = $1,450 × 104.64 = $151,728

Verification

Check: $151,728 at 8% for 15 years gives payment = $151,728 × 0.009557 = $1,450 ✓

Answer: $151,728.00 — You can afford about $45,514 less house with the shorter term, but you'll pay much less total interest.

2
Reverse the Unknown

You want to buy a $250,000 house with no down payment, using a 30-year loan at 8% interest. What would your monthly payment be?

Step 1 — Use the payment formula

PMT = P × [r(1 + r)^n] / [(1 + r)^n - 1] where P = $250,000

Step 2 — Calculate the bracket term

[0.006667 × (1.006667)^360] / [(1.006667)^360 - 1] = [0.006667 × 11.023] / [10.023] = 0.007333

Step 3 — Find monthly payment

PMT = $250,000 × 0.007333 = $1,833.25

Verification

Check using PV formula: $1,833.25 × 136.029 = $249,390.18 ≈ $250,000 ✓

Answer: $1,833.25 per month — About $383 more than your $1,450 budget.

3
Interest Rate Sensitivity

If interest rates drop to 6% (instead of 8%), still with a $1,450 monthly payment on a 30-year loan, what's the maximum house price?

Step 1 — New monthly rate

r = 6% ÷ 12 = 0.005, with n = 360 and PMT = $1,450

Step 2 — Calculate new PV factor

(1 - (1.005)^(-360)) / 0.005 = (1 - 0.1663) / 0.005 = 166.79

Step 3 — Find maximum house price

PV = $1,450 × 166.79 = $241,845

Verification

Check: $241,845 at 6% for 30 years gives payment = $241,845 × 0.005996 = $1,450 ✓

Answer: $241,845.50 — The 2 percentage point rate drop increases buying power by $44,603!

4
With Down Payment

You have $30,000 for a down payment. With the same $1,450 monthly payment on a 30-year loan at 8%, what's the maximum TOTAL house price you can afford?

Step 1 — Find maximum loan amount

Using our original calculation: Maximum loan = $197,242.05 (this hasn't changed)

Step 2 — Add the down payment

Total house price = Loan amount + Down payment

Total = $197,242.05 + $30,000 = $227,242.05

Step 3 — Verify the math

Down payment percentage: $30,000 ÷ $227,242.05 = 13.2%

This means you're financing $197,242.05, which we know produces exactly $1,450 monthly payments ✓

Final check

Loan-to-value ratio: $197,242.05 ÷ $227,242.05 = 86.8% — reasonable for most lenders.

Answer: $227,242.05 — The down payment increases your buying power by exactly $30,000.

Frequently Asked Questions

How do you calculate maximum loan amount from monthly payment?+
Use the present value of annuity formula: PV = PMT × [(1 - (1 + r)^(-n)) / r], where PMT is the monthly payment, r is the monthly interest rate, and n is the number of payments. In this problem, $1,450 × [(1 - (1.006667)^(-360)) / 0.006667] = $197,242.05. The key is converting the annual rate to monthly (8% ÷ 12) and using the total number of monthly payments (30 × 12 = 360).
What's the difference between annual and monthly interest rates in mortgage calculations?+
Annual rates must be converted to monthly rates by dividing by 12. An 8% annual rate becomes 8%/12 = 0.667% monthly. This monthly rate is used in all mortgage formulas since payments are monthly. Using the annual rate directly would incorrectly treat your $1,450 as an annual payment instead of monthly, giving a completely wrong answer.
Why is the present value formula used for mortgage calculations?+
A mortgage is essentially the present value of future payments. The loan amount today equals the sum of all future monthly payments discounted back to today's dollars. Here, 360 payments of $1,450 each have a present value of $197,242.05 at 8% annual interest. This reflects the time value of money—dollars paid in the future are worth less than dollars today.
DN
Dr. Neven Jurkovic
Professor of Mathematics • 15+ years teaching experience
Expert in financial mathematics and real-world problem solving
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-05-21