Find Assistant's Time Working Alone
What You Will Learn
- How to convert completion times into work rates (jobs per hour)
- Why work rates add when people collaborate on the same task
- Setting up and solving equations where the unknown appears in a denominator
- The relationship between individual capabilities and team productivity
- How to verify answers using the original rate equation
Solution: Method 1 — The Rate Addition Approach
The key insight is that when people work together, their work rates add up. Let's think of work rates as "fraction of the job completed per hour."
Step 1 — Define the work rates
Let t = the number of hours for the assistant to complete the job alone.
The worker completes the job in 10 hours, so the worker's rate is 1/10 of the job per hour.
The assistant completes the job in t hours, so the assistant's rate is 1/t of the job per hour.
Step 2 — Set up the combined rate equation
When working together, they complete the job in 6 hours. This means their combined rate is 1/6 of the job per hour.
Since rates add when people work together:
1/10 + 1/t = 1/6
Step 3 — Solve for t
To solve this equation, we'll get a common denominator and cross-multiply:
1/t = 1/6 - 1/10
1/t = 5/30 - 3/30
1/t = 2/30
1/t = 1/15
Therefore, t = 15 hours.
Step 4 — Interpret the result
The assistant, working alone, would take 15 hours to cover the parking lot with asphalt.
Solution: Method 2 — The Work Contribution Method
Instead of thinking about rates, let's think about how much work each person contributes during their 6-hour collaboration.
Step 1 — Calculate the worker's contribution
The worker's rate is 1/10 job per hour. In 6 hours of working together, the worker completes:
Step 2 — Find the assistant's contribution
Since the entire job is completed in 6 hours, and the worker does 3/5 of it, the assistant must do:
Step 3 — Calculate the assistant's rate
The assistant completes 2/5 of the job in 6 hours, so the assistant's rate is:
Step 4 — Find time for complete job
If the assistant works at 1/15 job per hour, then to complete 1 full job:
Verification
Let's check our answer by substituting back into the original rate equation:
- Worker's rate:
1/10job per hour - Assistant's rate:
1/15job per hour - Combined rate:
1/10 + 1/15
Perfect! A combined rate of 1/6 job per hour means they complete the job in 6 hours together, which matches the problem statement. ✓
The Tell-Tale Signs
You'll recognize work rate problems by these key phrases:
- "Working together" or "with help" — signals that rates need to be added
- "Working alone" — you're looking for individual completion times
- Time statements like "can complete in X hours" — convert these to rates of 1/X per hour
- Phrases like "fill a pool," "paint a house," "complete a project" — any task that can be measured as a fraction of completion
- "How long would it take..." — you're solving for time, which is the reciprocal of rate
Common Pitfalls
Mistake 1: Averaging the times
This logic treats time as if it averages linearly, but that's not how work rates combine. A very fast assistant (2 hours) plus the worker (10 hours) would complete the job much faster than 6 hours.
Mistake 2: Confusing rates and times
You can't add completion times directly. The equation should use rates: 1/10 + 1/t = 1/6. Adding times only works for sequential work, not parallel work.
Mistake 3: Forgetting to take the reciprocal
1/t = 1/15 and concluding t = 1/15 hours.
If 1/t = 1/15, then t = 15, not 1/15. The assistant takes 15 hours, not 4 minutes!
The Pattern Behind This
All work rate problems follow the same fundamental principle:
Where:
A = time for person/machine A alone
B = time for person/machine B alone
T = time when working together
This formula works because rates (jobs per hour) add when workers collaborate, but completion times don't. If you know any two of these three values, you can solve for the third.
Real Applications
This same mathematical structure appears everywhere:
- Computer processing: When two CPUs work on the same task, their processing rates combine exactly like work rates
- Manufacturing: Assembly lines with multiple workers or machines follow these same principles
- Parallel circuits: The reciprocal formula for electrical resistance in parallel is mathematically identical to work rates
- Pharmacokinetics: When multiple organs process a drug simultaneously, their clearance rates add just like work rates
What If?
Worker's rate: 1/12 job/hour, Combined rate: 1/5 job/hour. So: 1/12 + 1/t = 1/5
1/t = 1/5 - 1/12 = 12/60 - 5/60 = 7/60
t = 60/7 ≈ 8.57 hours, or 8 hours and 34 minutes
1/12 + 7/60 = 5/60 + 7/60 = 12/60 = 1/5 ✓
Worker completes (1/10) × 2 = 1/5 of the job in 2 hours
Remaining work: 1 - 1/5 = 4/5 of the job
Combined rate: 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6 job/hour
Time = (4/5) ÷ (1/6) = (4/5) × 6 = 24/5 = 4.8 hours
1/10 + 1/15 + 1/s = 1/3 where s is the trainee's solo time
1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6
1/6 + 1/s = 1/3, so 1/s = 1/3 - 1/6 = 2/6 - 1/6 = 1/6
The trainee takes s = 6 hours working alone
1/w + 1/12 = 1/4 where w is the worker's solo time
1/w = 1/4 - 1/12 = 3/12 - 1/12 = 2/12 = 1/6
w = 6 hours
1/6 + 1/12 = 2/12 + 1/12 = 3/12 = 1/4 ✓
Frequently Asked Questions
2026-08-22