Work Rate: Two Faucets Filling a Tank Together

Work Rate 9th-10th Grade
PROBLEM
It takes 2 hours for Faucet A to fill a tank, and it takes Faucet B 3 hours. How many hours will it take the two faucets to fill the tank together?

What You Will Learn

  • Converting completion times into work rates (reciprocals)
  • Adding work rates when multiple workers operate simultaneously
  • Converting combined rates back to completion times
  • Why averaging times gives the wrong answer (and what to do instead)
  • Setting up and solving fractional equations with common denominators

Solution: Method 1 — The Rate Addition Approach

The key insight is that work rates add together, not work times. When faucets work simultaneously, their individual rates of filling combine.

Step 1 — Find each faucet's rate

Convert the completion times to rates in "tanks per hour":

Faucet A rate = 1 tank ÷ 2 hours = 1/2 tank per hour
Faucet B rate = 1 tank ÷ 3 hours = 1/3 tank per hour

Step 2 — Add the rates together

When both faucets work together, their rates combine:

Combined rate = 1/2 + 1/3

To add these fractions, find a common denominator of 6:

1/2 + 1/3 = 3/6 + 2/6 = 5/6 tank per hour

Step 3 — Convert the combined rate to time

To find the time needed, take the reciprocal of the rate:

Time = 1 tank ÷ (5/6 tank per hour) = 1 × 6/5 = 6/5 = 1.2 hours

Step 4 — Convert to hours and minutes

Convert the decimal to a more readable format:

1.2 hours = 1 hour + 0.2 hours = 1 hour + 12 minutes

Solution: Method 2 — The Common Work Approach

Instead of working with fractions, we can imagine a larger amount of work that makes the arithmetic cleaner.

Step 1 — Choose a convenient total amount of work

Let's say the job is filling 6 tanks instead of 1 tank. Why 6? Because 6 is the least common multiple of 2 and 3, making our rates come out to whole numbers.

Step 2 — Find each faucet's rate in tanks per hour

Scale up the rates proportionally:

If Faucet A fills 1 tank in 2 hours, it fills 6 tanks in 12 hours
So Faucet A's rate = 6 tanks ÷ 12 hours = 3 tanks per hour

If Faucet B fills 1 tank in 3 hours, it fills 6 tanks in 18 hours
So Faucet B's rate = 6 tanks ÷ 18 hours = 2 tanks per hour

Step 3 — Find the combined rate and time

Working together, they fill 3 + 2 = 5 tanks per hour:

Time to fill 6 tanks = 6 tanks ÷ 5 tanks per hour = 6/5 = 1.2 hours

Step 4 — Scale back to the original problem

Since we want to fill just 1 tank, not 6 tanks:

Time for 1 tank = 1.2 hours ÷ 6 = 1.2 hours

Wait, that's not right! Let me recalculate. If they take 1.2 hours to fill 6 tanks together, then for 1 tank:

Time for 1 tank = 1.2 hours × (1 tank ÷ 6 tanks) = 1.2 ÷ 6 = 0.2 hours

Actually, let me restart this calculation properly:

Combined rate for 1 tank = 3/6 + 2/6 = 5/6 tank per hour
Time = 1 ÷ (5/6) = 6/5 = 1.2 hours
6/5 hours = 1.2 hours = 1 hour and 12 minutes

Verification

Let's verify our answer by checking how much of the tank each faucet fills in 1.2 hours:

Faucet A in 1.2 hours: (1/2 tank per hour) × 1.2 hours = 0.6 tanks
Faucet B in 1.2 hours: (1/3 tank per hour) × 1.2 hours = 0.4 tanks
Total: 0.6 + 0.4 = 1.0 tank ✓

Perfect! Together they fill exactly one full tank in 1.2 hours.

We can also verify using the general formula. For work rate problems, if individual times are a and b, the combined time is:

Combined time = (a × b) ÷ (a + b) = (2 × 3) ÷ (2 + 3) = 6 ÷ 5 = 1.2 hours ✓

Watch Out For These

✗ Averaging the times

Wrong calculation: (2 hours + 3 hours) ÷ 2 = 2.5 hours

Why it's wrong: This suggests that working together takes longer than either faucet working alone, which defies logic. The temptation to average is strong because it's what we do in many other contexts, but here rates add, not times.

✗ Adding times instead of rates

Wrong setup: Total time = 2 hours + 3 hours = 5 hours

Why it's wrong: This treats the faucets as working sequentially (one after the other) rather than simultaneously. The problem clearly states they work together, so their rates combine, not their completion times.

✗ Forgetting to take the reciprocal

Wrong final step: Combined rate = 5/6, so answer = 5/6 hours

Why it's wrong: The rate tells you how much work gets done per hour, not how many hours the work takes. To convert from "5/6 tank per hour" to "how long for 1 tank," you must divide: 1 ÷ (5/6) = 6/5 hours.

The General Pattern

This problem follows the universal pattern for combined work rates. When workers operate simultaneously, their rates are additive:

If individual times are t₁, t₂, t₃, ...
Then individual rates are 1/t₁, 1/t₂, 1/t₃, ...
Combined rate = 1/t₁ + 1/t₂ + 1/t₃ + ...
Combined time = 1 ÷ (combined rate)

For the special case of just two workers, this simplifies to the harmonic mean formula:

Combined time = (t₁ × t₂) ÷ (t₁ + t₂)

In our problem: (2 × 3) ÷ (2 + 3) = 6 ÷ 5 = 1.2 hours.

Important: This formula only works when all workers are doing the same task simultaneously. If they work at different times, take breaks, or work on different parts of the job, you need to set up the problem step by step.

Real Applications

This exact calculation appears throughout engineering and operations:

Manufacturing: Two assembly lines producing the same product — Line A completes 50 units/hour, Line B completes 30 units/hour, together they produce 80 units/hour.

Computer networks: Parallel data streams with different bandwidths combine their rates when downloading the same file from multiple sources.

Pharmacology: When the body eliminates a drug through multiple pathways (kidney and liver), the clearance rates add to give total elimination rate.

How to Spot This Problem Type

Look for these telltale phrases that signal a combined work rate problem:

  • "...working together..." or "...both at the same time..."
  • "How long will it take if..." followed by multiple workers
  • Individual completion times given, combined time unknown
  • Jobs involving filling, emptying, building, or producing

Variation alert: Sometimes the problem involves one thing helping and another thing hindering (like a faucet filling while a drain empties). In that case, subtract the hindrance rate from the help rate.

Red flag phrases: "Taking turns" or "one after the other" signal sequential work, not combined work — those are different problem types entirely.

What If?

1
Adding a Drain
Faucet A fills the tank in 2 hours, Faucet B fills it in 3 hours, but Drain C can empty the full tank in 6 hours. If all three are opened at once, how long to fill the tank?
Step 1 — Find all rates

Faucet A: 1/2 tank/hour, Faucet B: 1/3 tank/hour, Drain C: -1/6 tank/hour (negative because it empties)

Step 2 — Combine rates

Net rate = 1/2 + 1/3 - 1/6 = 3/6 + 2/6 - 1/6 = 4/6 = 2/3 tank/hour

Step 3 — Calculate time

Time = 1 ÷ (2/3) = 3/2 = 1.5 hours

Verification

In 1.5 hours: A fills 0.75 tanks, B fills 0.5 tanks, C drains 0.25 tanks. Net: 0.75 + 0.5 - 0.25 = 1.0 tank ✓

Answer: 1.5 hours = 1 hour 30 minutes

2
Sequential Start
Faucet A runs alone for 30 minutes, then Faucet B is turned on and they finish together. How long does it take to fill the tank from when A started?
Step 1 — Find how much A fills in 30 minutes

In 0.5 hours, Faucet A fills: (1/2) × 0.5 = 1/4 of the tank

Step 2 — Find remaining work

Remaining to fill: 1 - 1/4 = 3/4 of the tank

Step 3 — Find time for both working together

Combined rate: 1/2 + 1/3 = 5/6 tank/hour. Time for 3/4 tank: (3/4) ÷ (5/6) = (3/4) × (6/5) = 18/20 = 0.9 hours

Step 4 — Add total time

Total time = 0.5 + 0.9 = 1.4 hours = 1 hour 24 minutes

Answer: 1.4 hours = 1 hour 24 minutes

3
Reverse the Unknown
Faucets A and B together fill the tank in 1.2 hours. If Faucet A alone takes 2 hours, how long does Faucet B alone take?
Step 1 — Set up rate equation

Combined rate = 1/1.2 = 5/6 tank/hour. Faucet A rate = 1/2 tank/hour. Let Faucet B time = t hours.

Step 2 — Write the equation

1/2 + 1/t = 5/6

Step 3 — Solve for t

1/t = 5/6 - 1/2 = 5/6 - 3/6 = 2/6 = 1/3. Therefore t = 3

Verification

Check: 1/2 + 1/3 = 3/6 + 2/6 = 5/6 ✓, and 1 ÷ (5/6) = 6/5 = 1.2 hours ✓

Answer: Faucet B alone takes 3 hours

4
Three Faucets
Faucet A fills a tank in 2 hours, Faucet B in 3 hours, and Faucet C in 6 hours. How long for all three working together?
Step 1 — Find individual rates

Faucet A: 1/2 tank/hour, Faucet B: 1/3 tank/hour, Faucet C: 1/6 tank/hour

Step 2 — Add all rates

Combined rate = 1/2 + 1/3 + 1/6. Common denominator is 6: 3/6 + 2/6 + 1/6 = 6/6 = 1 tank/hour

Step 3 — Calculate time

Time = 1 tank ÷ 1 tank/hour = 1 hour

Verification

In 1 hour: A fills 0.5 tanks, B fills 0.33 tanks, C fills 0.167 tanks. Total: 0.5 + 0.33 + 0.167 = 1.0 tank ✓

Answer: 1 hour exactly

Frequently Asked Questions

How do you calculate the time when two workers complete a task together?+
Find each worker's rate (1/time), add the rates together, then take the reciprocal. For example, if one faucet fills a tank in 2 hours (rate = 1/2 tank/hour) and another in 3 hours (rate = 1/3 tank/hour), their combined rate is 1/2 + 1/3 = 5/6 tank/hour, so together they take 6/5 = 1.2 hours.
Why can't you just average the individual work times?+
Averaging times gives the wrong answer because rates add, not times. If you average 2 hours and 3 hours to get 2.5 hours, you're saying the combined work is slower than the faster individual worker, which makes no sense. The correct approach is to add the work rates (1/2 + 1/3 = 5/6) then invert to get time (6/5 = 1.2 hours).
What's the general formula for combined work problems?+
For any number of workers with individual times t₁, t₂, t₃..., the combined time T satisfies: 1/T = 1/t₁ + 1/t₂ + 1/t₃ + ... This works because rates (work per unit time) are additive, and rate equals 1/time.
DN

Dr. Neven Jurkovic

Mathematics Professor & Educational Technology Specialist

NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-06-14