Work Rate: Two Faucets Filling a Tank Together
What You Will Learn
- Converting completion times into work rates (reciprocals)
- Adding work rates when multiple workers operate simultaneously
- Converting combined rates back to completion times
- Why averaging times gives the wrong answer (and what to do instead)
- Setting up and solving fractional equations with common denominators
Solution: Method 1 — The Rate Addition Approach
The key insight is that work rates add together, not work times. When faucets work simultaneously, their individual rates of filling combine.
Step 1 — Find each faucet's rate
Convert the completion times to rates in "tanks per hour":
Faucet B rate = 1 tank ÷ 3 hours = 1/3 tank per hour
Step 2 — Add the rates together
When both faucets work together, their rates combine:
To add these fractions, find a common denominator of 6:
Step 3 — Convert the combined rate to time
To find the time needed, take the reciprocal of the rate:
Step 4 — Convert to hours and minutes
Convert the decimal to a more readable format:
Solution: Method 2 — The Common Work Approach
Instead of working with fractions, we can imagine a larger amount of work that makes the arithmetic cleaner.
Step 1 — Choose a convenient total amount of work
Let's say the job is filling 6 tanks instead of 1 tank. Why 6? Because 6 is the least common multiple of 2 and 3, making our rates come out to whole numbers.
Step 2 — Find each faucet's rate in tanks per hour
Scale up the rates proportionally:
So Faucet A's rate = 6 tanks ÷ 12 hours = 3 tanks per hour
If Faucet B fills 1 tank in 3 hours, it fills 6 tanks in 18 hours
So Faucet B's rate = 6 tanks ÷ 18 hours = 2 tanks per hour
Step 3 — Find the combined rate and time
Working together, they fill 3 + 2 = 5 tanks per hour:
Step 4 — Scale back to the original problem
Since we want to fill just 1 tank, not 6 tanks:
Wait, that's not right! Let me recalculate. If they take 1.2 hours to fill 6 tanks together, then for 1 tank:
Actually, let me restart this calculation properly:
Time = 1 ÷ (5/6) = 6/5 = 1.2 hours
Verification
Let's verify our answer by checking how much of the tank each faucet fills in 1.2 hours:
Faucet B in 1.2 hours: (1/3 tank per hour) × 1.2 hours = 0.4 tanks
Total: 0.6 + 0.4 = 1.0 tank ✓
Perfect! Together they fill exactly one full tank in 1.2 hours.
We can also verify using the general formula. For work rate problems, if individual times are a and b, the combined time is:
Watch Out For These
Wrong calculation: (2 hours + 3 hours) ÷ 2 = 2.5 hours
Why it's wrong: This suggests that working together takes longer than either faucet working alone, which defies logic. The temptation to average is strong because it's what we do in many other contexts, but here rates add, not times.
Wrong setup: Total time = 2 hours + 3 hours = 5 hours
Why it's wrong: This treats the faucets as working sequentially (one after the other) rather than simultaneously. The problem clearly states they work together, so their rates combine, not their completion times.
Wrong final step: Combined rate = 5/6, so answer = 5/6 hours
Why it's wrong: The rate tells you how much work gets done per hour, not how many hours the work takes. To convert from "5/6 tank per hour" to "how long for 1 tank," you must divide: 1 ÷ (5/6) = 6/5 hours.
The General Pattern
This problem follows the universal pattern for combined work rates. When workers operate simultaneously, their rates are additive:
Then individual rates are 1/t₁, 1/t₂, 1/t₃, ...
Combined rate = 1/t₁ + 1/t₂ + 1/t₃ + ...
Combined time = 1 ÷ (combined rate)
For the special case of just two workers, this simplifies to the harmonic mean formula:
In our problem: (2 × 3) ÷ (2 + 3) = 6 ÷ 5 = 1.2 hours.
Real Applications
This exact calculation appears throughout engineering and operations:
Manufacturing: Two assembly lines producing the same product — Line A completes 50 units/hour, Line B completes 30 units/hour, together they produce 80 units/hour.
Computer networks: Parallel data streams with different bandwidths combine their rates when downloading the same file from multiple sources.
Pharmacology: When the body eliminates a drug through multiple pathways (kidney and liver), the clearance rates add to give total elimination rate.
How to Spot This Problem Type
Look for these telltale phrases that signal a combined work rate problem:
- "...working together..." or "...both at the same time..."
- "How long will it take if..." followed by multiple workers
- Individual completion times given, combined time unknown
- Jobs involving filling, emptying, building, or producing
Variation alert: Sometimes the problem involves one thing helping and another thing hindering (like a faucet filling while a drain empties). In that case, subtract the hindrance rate from the help rate.
Red flag phrases: "Taking turns" or "one after the other" signal sequential work, not combined work — those are different problem types entirely.
What If?
Faucet A: 1/2 tank/hour, Faucet B: 1/3 tank/hour, Drain C: -1/6 tank/hour (negative because it empties)
Net rate = 1/2 + 1/3 - 1/6 = 3/6 + 2/6 - 1/6 = 4/6 = 2/3 tank/hour
Time = 1 ÷ (2/3) = 3/2 = 1.5 hours
In 1.5 hours: A fills 0.75 tanks, B fills 0.5 tanks, C drains 0.25 tanks. Net: 0.75 + 0.5 - 0.25 = 1.0 tank ✓
Answer: 1.5 hours = 1 hour 30 minutes
In 0.5 hours, Faucet A fills: (1/2) × 0.5 = 1/4 of the tank
Remaining to fill: 1 - 1/4 = 3/4 of the tank
Combined rate: 1/2 + 1/3 = 5/6 tank/hour. Time for 3/4 tank: (3/4) ÷ (5/6) = (3/4) × (6/5) = 18/20 = 0.9 hours
Total time = 0.5 + 0.9 = 1.4 hours = 1 hour 24 minutes
Answer: 1.4 hours = 1 hour 24 minutes
Combined rate = 1/1.2 = 5/6 tank/hour. Faucet A rate = 1/2 tank/hour. Let Faucet B time = t hours.
1/2 + 1/t = 5/6
1/t = 5/6 - 1/2 = 5/6 - 3/6 = 2/6 = 1/3. Therefore t = 3
Check: 1/2 + 1/3 = 3/6 + 2/6 = 5/6 ✓, and 1 ÷ (5/6) = 6/5 = 1.2 hours ✓
Answer: Faucet B alone takes 3 hours
Faucet A: 1/2 tank/hour, Faucet B: 1/3 tank/hour, Faucet C: 1/6 tank/hour
Combined rate = 1/2 + 1/3 + 1/6. Common denominator is 6: 3/6 + 2/6 + 1/6 = 6/6 = 1 tank/hour
Time = 1 tank ÷ 1 tank/hour = 1 hour
In 1 hour: A fills 0.5 tanks, B fills 0.33 tanks, C fills 0.167 tanks. Total: 0.5 + 0.33 + 0.167 = 1.0 tank ✓
Answer: 1 hour exactly
Frequently Asked Questions
2026-06-14