We need to convert this complex fraction into a division problem by replacing the main fraction line with the division symbol: AB=A÷B. In our example, A is equal to 2x+2 and B is equal to 3. |
We need to perform a division by multiplying the dividend with the reciprocal of the divisor. The following rule is applied: (AB)÷(CD)=(AB)(DC) In our example, A is equal to 2 and B is equal to x+2. C is equal to 3 and D is equal to 1. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
We need to perform a multiplication. The following rule is applied: AB·CD=ACBD In our example, the factors in the new numerator are: 2, 1, The factors in the new denominator are: (x+2), 3, |
Number 1 as a factor, does not need to be explicitly written. In other words: 1A=A. In our example, the above transformation has been applied once. |
Numerical terms are commonly written first. |
We need to convert this complex fraction into a division problem by replacing the main fraction line with the division symbol: AB=A÷B. In our example, A is equal to 23(x+2) and B is equal to x+2. |
We need to perform a division by multiplying the dividend with the reciprocal of the divisor. The following rule is applied: (AB)÷(CD)=(AB)(DC) In our example, A is equal to 2 and B is equal to 3(x+2). C is equal to x+2 and D is equal to 1. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
We need to perform a multiplication. The following rule is applied: AB·CD=ACBD In our example, the factors in the new numerator are: 2, 1, The factors in the new denominator are: 3, (x+2), (x+2), |
Number 1 as a factor, does not need to be explicitly written. In other words: 1A=A. In our example, the above transformation has been applied once. |
We need to combine like factors in this term by adding up all the exponents and copying the base. No exponent implies the value of 1. The following are like factors: (x+2), (x+2) |
Numerical terms in this expression have been added. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
We need to add fractions. The following rule is applied: AB+CD=LCDBA+LCDDCLCD This example involves 3 terms. The LCD is equal to: x·3(x+2)2 |
We need to get rid of parentheses in this term. All the negative factors will change sign. In our example, we do not have any negative factors. The sign of the term will not change. |
Numerical terms are commonly written first. |
We need to get rid of parentheses in this term. All the negative factors will change sign. In our example, we have only one negative factor. The sign of the term will change, since there is an odd number of negative factors. |
Numerical terms are commonly written first. |
We need to organize this term into groups of like factors, so we can combine them easier. The following are like factors: 3, 3 |
Numerical terms are commonly written first. |
Numerical factors in this term have been multiplied. |
Numerical factors in this term have been multiplied. |
We need to organize this expression into groups of like terms, so we can combine them easier. There is only one group of like terms: 9(x+2)2, −6(x+2)2 |
We need to combine like terms in this expression by adding up all numerical coefficients and copying the literal part, if any. No numerical coefficient implies value of 1. There is only one group of like terms: 9(x+2)2, −6(x+2)2 |
We need to square a binomial. The following rule is applied: A2+2AB+B2=(A+B)2 In our example, A is equal to x, B is equal to 2 and N is equal to 2. |
We need to organize this term into groups of like factors, so we can combine them easier. The following are like factors: 2, 2 |
We need to evaluate a power by multiplying the base by itself as many times as the exponent indicates. In our example, base 2 will be multiplied by itself twice. |
Numerical factors in this term have been multiplied. |
We need to expand this term by multiplying a term and an expression. The following product distributive property will be used: A(B+C)=AB+AC. In our example, the resulting expression will consist of 3 terms: the first term is a product of 3 and x2. the second term is a product of 3 and 4x. the third term is a product of 3 and 4. |
Numerical factors in this term have been multiplied. |
Numerical factors in this term have been multiplied. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
We need to organize this expression into groups of like terms, so we can combine them easier. There is only one group of like terms: 12x, 2x |
We need to combine like terms in this expression by adding up all numerical coefficients and copying the literal part, if any. No numerical coefficient implies value of 1. There is only one group of like terms: 12x, 2x |