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Created on: 2012-04-14

A sample problem solved by Quickmath math solver

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Expression

(x*(1+x)^t/((1+x)^t-1)-y*(1+y)^t/((1+y)^t-1))/(x-y)

  1. A fraction: the top of the fraction is a sum containing 2 terms; the first term of the sum is equal to a quotient: dividend of the quotient is a product consisting of 2 factors; the first factor of the product is equal to x; the second factor of the product is a power; the base is a sum consisting of 2 terms; the first term of the sum is one; the second term of the sum is equal to x; the exponent is t; divisor of the quotient is a sum comprising 2 terms; the first term of the sum is equal to a power; the base is a sum consisting of 2 terms; the first term of the sum is equal to one; the second term of the sum is equal to x; the exponent is t; the second term of the sum is equal to negative one; the second term of the sum is equal to a negative quotient: dividend of the quotient is a product containing 2 factors; the first factor of the product is equal to y; the second factor of the product is a power; the base is a sum that contains 2 terms; the first term of the sum is equal to one; the second term of the sum is equal to y; the exponent is t; divisor of the quotient is a sum that consists of 2 terms; the first term of the sum is equal to a power; the base is a sum consisting of 2 terms; the first term of the sum is equal to one; the second term of the sum is equal to y; the exponent is t; the second term of the sum is negative one; the bottom of the fraction is a sum consisting of 2 terms; the first term of the sum is equal to x; the second term of the sum is equal to negative y;
  2. x multiplied by left parenthesis one plus x right parenthesis to the power t fraction line open bracket one plus x close bracket raised to the power t plus negative one plus negative y multiplied by open brace one plus y close brace raised to the power of t divided by opening parenthesis one plus y closing parenthesis to the power of t plus negative one fraction line x plus negative y;

Result

((y+1)^t*(((x+1)^t-1)*y-x*(x+1)^t)+x*(x+1)^t)/((y+1)^t*(((x+1)^t-1)*y-x*(x+1)^t+x)+(1-(x+1)^t)*y+x*(x+1)^t-x)

  1. A fraction: the top of the fraction is a sum of 2 terms; the first term of the sum is equal to a product containing 2 factors; the first factor of the product is a power; the base is a sum that consists of 2 terms; the first term of the sum is y; the second term of the sum is equal to one; the exponent is t; the second factor of the product is equal to a sum that comprises 2 terms; the first term of the sum is equal to a product of 2 factors; the first factor of the product is equal to a sum consisting of 2 terms; the first term of the sum is equal to a power; the base is a sum that contains 2 terms; the first term of the sum is x; the second term of the sum is equal to one; the exponent is t; the second term of the sum is equal to negative one; the second factor of the product is equal to y; the second term of the sum is a negative product comprising 2 factors; the first factor of the product is equal to x; the second factor of the product is equal to a power; the base is a sum that contains 2 terms; the first term of the sum is equal to x; the second term of the sum is one; the exponent is t; the second term of the sum is equal to a product containing 2 factors; the first factor of the product is x; the second factor of the product is a power; the base is a sum of 2 terms; the first term of the sum is x; the second term of the sum is one; the exponent is t; the bottom of the fraction is a sum comprising 4 terms; the first term of the sum is equal to a product of 2 factors; the first factor of the product is equal to a power; the base is a sum of 2 terms; the first term of the sum is equal to y; the second term of the sum is equal to one; the exponent is t; the second factor of the product is a sum that consists of 3 terms; the first term of the sum is a product that consists of 2 factors; the first factor of the product is equal to a sum that contains 2 terms; the first term of the sum is equal to a power; the base is a sum consisting of 2 terms; the first term of the sum is equal to x; the second term of the sum is equal to one; the exponent is t; the second term of the sum is negative one; the second factor of the product is y; the second term of the sum is a negative product that comprises 2 factors; the first factor of the product is x; the second factor of the product is a power; the base is a sum of 2 terms; the first term of the sum is equal to x; the second term of the sum is equal to one; the exponent is t; the third term of the sum is equal to x; the second term of the sum is a product that contains 2 factors; the first factor of the product is equal to a sum that consists of 2 terms; the first term of the sum is equal to one; the second term of the sum is a negative power; the base is a sum consisting of 2 terms; the first term of the sum is x; the second term of the sum is equal to one; the exponent is t; the second factor of the product is y; the third term of the sum is equal to a product of 2 factors; the first factor of the product is x; the second factor of the product is a power; the base is a sum of 2 terms; the first term of the sum is x; the second term of the sum is equal to one; the exponent is t; the four term of the sum is equal to negative x;
  2. left brace y plus one right brace raised to the power of t multiplied by left bracket open bracket left bracket x plus one right bracket raised to the power of t plus negative one close bracket multiplied by y plus negative x times opening brace x plus one closing brace exponentiated by t right bracket plus x times opening brace x plus one closing brace to the power of t over left parenthesis y plus one right parenthesis to the power t multiplied by opening bracket opening brace left bracket x plus one right bracket to the power of t plus negative one closing brace multiplied by y plus negative x multiplied by open bracket x plus one close bracket exponentiated by t plus x closing bracket plus opening bracket one plus negative left bracket x plus one right bracket exponentiated by t closing bracket multiplied by y plus x times opening brace x plus one closing brace to the power t plus negative x.