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Created on: 2012-04-13

A sample problem solved by Quickmath math solver

Command

Expand

Expression

n*(n-1)*(n-2)*(n-3)*(n-4)

  1. A product that comprises 5 factors. The first factor of the product is n. The second factor of the product is equal to a sum that comprises 2 terms. The first term of the sum is equal to n. The second term of the sum is negative one. The third factor of the product is equal to a sum comprising 2 terms. The first term of the sum is equal to n. The second term of the sum is equal to negative two. The four factor of the product is equal to a sum that comprises 2 terms. The first term of the sum is equal to n. The second term of the sum is equal to negative three. The five factor of the product is equal to a sum that consists of 2 terms. The first term of the sum is equal to n. The second term of the sum is equal to negative four.
  2. n multiplied by left bracket n plus negative one right bracket times opening bracket n plus negative two closing bracket times opening brace n plus negative three closing brace multiplied by open brace n plus negative four close brace;

Result

n^5-10*n^4+35*n^3-50*n^2+24*n

  1. A sum comprising 5 terms. The first term of the sum is equal to a power. The base is n. The exponent is five. The second term of the sum is equal to a negative product that consists of 2 factors. The first factor of the product is equal to ten. The second factor of the product is a power. The base is n. The exponent is four. The third term of the sum is equal to a product that contains 2 factors. The first factor of the product is thirty five. The second factor of the product is equal to a power. The base is n. The exponent is three. The four term of the sum is equal to a negative product comprising 2 factors. The first factor of the product is equal to fifty. The second factor of the product is a power. The base is n. The exponent is two. The five term of the sum is equal to a product that comprises 2 factors. The first factor of the product is twenty four. The second factor of the product is equal to n.
  2. n exponentiated by five plus negative ten times n exponentiated by four plus thirty five multiplied by n raised to the power of three plus negative fifty multiplied by n to the power of two plus twenty four times n.