finding solution to 2*x^2+4 = 0 equation :: QuickMath.com

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Created on: 2012-02-19

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an equation LHS is equal to a sum that consists of 2 terms; the first term of the sum is equal to a product that comprises 2 factors; the first factor of the product is equal to two; the second factor of the product is equal to a power; the base is x; the exponent is two; the second term of the sum is four Right side of the equation is zero;
two times x to the power two plus four is equal to zero;

Exact

Solution 1 ( complex )

an equation Left side of the equation is equal to x Right side of the equation is a product that contains 2 factors; the first factor of the product is equal to negative square root of two; the second factor of the product is equal to i;
x is negative square root of two multiplied by i.

Solution 2 ( complex )

an equation Left side of the equation is equal to x Right side of the equation is equal to a product comprising 2 factors; the first factor of the product is equal to square root of two; the second factor of the product is equal to i;
x is equal to square root of two multiplied by i.

Approximate

Solution 1 ( complex )

an equation LHS is equal to x RHS is equal to a product consisting of 2 factors. The first factor of the product is negative one point four tenth, one hundredth, four ten hundredth, two thousandth and one ten thousandth. The second factor of the product is equal to i.
x is negative one point four tenth, one hundredth, four ten hundredth, two thousandth and one ten thousandth times i;

Solution 2 ( complex )

an equation Left side of the equation is equal to x RHS is equal to a product that contains 2 factors. The first factor of the product is equal to one point four one four two one. The second factor of the product is equal to i.
x is equal to one point four one four two one times i;